MSA线性分析表量具型量具编量具名称：号：号：测试人测试日被测参数：员：期：样品编号12345判定依据基准值(Xi)测试次数测量值偏倚测量值偏倚测量值偏倚测量值偏倚测量值偏倚1、偏倚=0整条直线在10.0000.0000.0000.0000.000置信区间内，系统可20.0000.0000.0000.0000.000接受，否则为不可接30.0000.0000.0000.0000.000受；40.0000.0000.0000.0000.00050.0000.0000.0000.0000.0002、t≤t，agm-2,1-α/260.0000.0000.0000.0000.000系统可接受，否则为70.0000.0000.0000.0000.000不可接受80.0000.0000.0000.0000.00090.0000.0000.0000.0000.000100.0000.0000.0000.0000.000110.0000.0000.0000.0000.000120.0000.0000.0000.0000.000偏倚平均值(y)0.000000.000000.000000.000000.00000∑y=0.00000i零件均值#DIV/0!#DIV/0!#DIV/0!#DIV/0!#DIV/0!∑x=0.00极差(R)0.00000.00000.00000.00000.0000(∑x)2=0xi×yi#DIV/0!#DIV/0!#DIV/0!#DIV/0!#DIV/0!∑XY=0.00000x2#DIV/0!#DIV/0!#DIV/0!#DIV/0!#DIV/0!∑X2=0.0y20.0000000000.0000000000.0000000000.0000000000.000000000∑Y2=0.000000∑(x-x(x-x)2#DIV/0!#DIV/0!#DIV/0!#DIV/0!#DIV/0!i平0.000平均)2=均1xyXYy2byiaxygmSiii斜率a#DIV/0!#DIV/0!1gm2x2x2gm[∑xy-∑x(∑y)/n]2截距byax#DIV/0!t=2.00172R-Sq=#DIV/0!gm-2,1-α/2[∑x2-(∑x)2/n]×[∑y2-(∑y)2/n]对于一个已知的X0,α=0.05,由t-分布表,取(gm-2)=58个自由度,并取概率为0.975偏倚=b+ax#DIV/0!#DIV/0!#DIV/0!#DIV/0!#DIV/0!│t│=上限：下限：a1??1???2?#DIV/0!1xx2?2???1xx?2?b+ax+?t+0?Sb+ax?t+0?Sa?a?0gm2,1gm?20gm2,1gm?22xx???2xx??│t│=ii?b下限#DIV/0!#DIV/0!#DIV/0!#DIV/0!#DIV/0!#DIV/0!上限#DIV/0!#DIV/0!#DIV/0!#DIV/0!#DIV/0!1.0000y=b+ax上限下限0.8000结论######0.60000.40000.20000.00000.0000.0000.0000.0000.000审核制定