JC02阶梯基础计算4.作用在基础顶部荷载标准组合值F=327.500kN项目名称_____________日期_____________Mx=23.000kN*m设计者_____________校对者_____________My=0.600kN*m一、设计依据Vx=1.400kN《建筑地基基础设计规范》(GB50007-2002)①Vy=46.800kN《混凝土结构设计规范》(GB50010-2002)②ks=1.25二、示意图Fk=F/ks=327.500/1.25=262.000kNMxk=Mx/ks=23.000/1.25=18.400kN*mMyk=My/ks=0.600/1.25=0.480kN*mVxk=Vx/ks=1.400/1.25=1.120kNVyk=Vy/ks=46.800/1.25=37.440kN5.修正后的地基承载力特征值fa=180.000kPa四、计算参数1.基础总长Bx=b1+b2+bc=0.600+0.600+0.300=1.500m2.基础总宽By=a1+a2+hc=0.500+0.500+0.400=1.400mA1=a1+hc/2=0.500+0.400/2=0.700mA2=a2+hc/2=0.500+0.400/2=0.700mB1=b1+bc/2=0.600+0.300/2=0.750mB2=b2+bc/2=0.600+0.300/2=0.750m3.基础总高H=h1=0.300=0.300m4.底板配筋计算高度ho=h1-as=0.300-0.040=0.260m5.基础底面积A=Bx*By=1.500*1.400=2.100m26.Gk=γ*Bx*By*dh=20.000*1.500*1.400*1.500=63.000kNG=1.35*Gk=1.35*63.000=85.050kN五、计算作用在基础底部弯矩值三、计算信息Mdxk=Mxk-Vyk*H=18.400-37.440*0.300=7.168kN*m构件编号:JC-1计算类型:自动计算截面尺寸Mdyk=Myk+Vxk*H=0.480+1.120*0.300=0.816kN*m1.几何参数Mdx=Mx-Vy*H=23.000-46.800*0.300=8.960kN*m台阶数n=1Mdy=My+Vx*H=0.600+1.400*0.300=1.020kN*m矩形柱宽bc=300mm矩形柱高hc=400mm六、验算地基承载力基础高度h1(自动计算)=300mm1.验算轴心荷载作用下地基承载力一阶长度b1=600mmb2=600mm一阶宽度a1=500mma2=500mmpk=(Fk+Gk)/A=(262.000+63.000)/2.100=154.762kPa【①5.2.1-2】2.材料信息因γo*pk=1.0*154.762=154.762kPa≤fa=180.000kPa基础混凝土等级:C30ft_b=1.43N/mm2fc_b=14.3N/mm2轴心荷载作用下地基承载力满足要求柱混凝土等级:C30ft_c=1.43N/mm2fc_c=14.3N/mm22.验算偏心荷载作用下的地基承载力钢筋级别:HRB400fy=360N/mm2exk=Mdyk/(Fk+Gk)=0.816/(262.000+63.000)=0.003m3.计算信息因|exk|≤Bx/6=0.250mx方向小偏心,结构重要性系数:γo=1.0由公式【①5.2.2-2】和【①5.2.2-3】推导基础埋深:dh=1.500mPkmax_x=(Fk+Gk)/A+6*|Mdyk|/(Bx2*By)纵筋合力点至近边距离:as=40mm=(262.000+63.000)/2.100+6*|0.816|/(1.5002*1.400)基础及其上覆土的平均容重:γ=20.000kN/m3=156.316kPa最小配筋率:ρmin=0.150%Pkmin_x=(Fk+Gk)/A-6*|Mdyk|/(Bx2*By)=(262.000+63.000)/2.100-6*|0.816|/(1.5002*1.400)Pjmax_x=Pmax_x-G/A=198.395-85.050/2.100=157.895kPa=153.208kPaPjmax_y=Pmax_y-G/A=214.738-85.050/2.100=174.238kPaeyk=Mdxk/(Fk+Gk)=7.168/(262.000+63.000)=0.022m2.验算柱边冲切因|eyk|≤By/6=0.233my方向小偏心YH=h1=0.300m,YB=bc=0.300m,YL