混凝土强度统计方法评定计算程序数据输入自动计算评定fcu,k=序号计算公式计算值∑00.01n(组数）=0.0nfcu,if2cu,i2λ1=1.710.03λ2=0.920.04mfcu=#DIV/0!30.05sfcu"=#DIV/0!40.060.06fcu,k=0.050.07sfcu=#DIV/0!60.08mfcu-λ1sfcu=#DIV/0!70.090.9fcu,k=0.080.010mfcu-λ1sfcu#DIV/0!0.9fcu,k90.011fcu,min=0.00100.012λ2fcu,k=0.000110.013fcu,min≥λ2fcu,k120.0140.85Fcu,k=0130.0150.95Fcu,k=0140.0161.15Fcu,k=0150.017合格与不合格＝#DIV/0!160.0170.0180.0公式提供者：张志勇190.0200.0编写：黄瑞府210.0QQ：87906189220.0电子邮箱：huang7654@163.com230.0huangruifu@21cn.com240.0250.0260.0270.0280.0290.0300.0310.0320.0330.0340.0350.0360.0370.0380.0390.0400.0410.0420.0430.0440.0450.0460.0470.0480.0490.0500.0510.0520.0530.0540.0550.0560.0570.0580.0590.0600.0610.0620.0630.0640.0650.0660.0670.0680.0690.0700.0710.0720.0730.0740.0750.0760.0770.0780.0790.0800.0810.0820.0830.0840.0850.0860.0870.0880.0890.0900.0910.0920.0930.0940.0950.0960.0970.0980.0990.01000.01010.01020.01030.01040.01050.01060.01070.01080.01090.01100.01110.01120.01130.01140.01150.01160.01170.01180.01190.01200.01210.01220.01230.01240.01250.01260.01270.01280.01290.01300.01310.01320.01330.01340.01350.01360.01370.01380.01390.01400.01410.01420.01430.01440.01450.01460.01470.01480.01490.01500.01510.01520.01530.01540.01550.01560.01570.01580.01590.01600.01610.01620.01630.01640.01650.01660.01670.01680.01690.01700.01710.01720.01730.01740.01750.01760.01770.01780.01790.01800.01810.01820.01830.01840.01850.01860.01870.01880.01890.01900.01910.01920.01930.01940.01950.01960.01970.01980.01990.02000.02010.02020.02030.02040.02050.02060.02070.02080.02090.02100.02110.02120.02130.02140.02150.02160.02170.02180.02190.02200.02210.02220.02230.02240.02250.02260.02270.02280.02290.02300.02310.02320.02330.02340.02350.02360.02370.02380.02390.02400.02410.02420.02430.02440.02450.02460.02470.02480.02490.02500.02510.02520.02530.02540.02550.02560.02570.02580.02590.02600.02610.02620.02630.02640.02650.02660.02670.02680.02690.02700.02710.02720.02730.02740.02750.02760.02770.02780.02790.02800.02810.02820.02830.02840.02850.02860.02870.02880.02890.02900.02910