答案网（http://www.daanwang.com）部分习题答案（仅供参考，不对之处敬请批评指正，谢谢！）（2-2题~2-4题）2-2(a)mxt()ofxtxt[1(i)--o()]2ofxt()mx(t)(f即：o1f)x(t)2o1ifx(t)(b)f(kk1)x(t)2okk12x(t)o2kifx(t)fxt)(c()()()()()ok+1kxt+2o=fxti+1ikxtRRCCu(t)(RC2-3(a)121o2+11+2RC2+1oRC)u(t)2+ou(t)RRCCu(t)(RC=121i2+11+22RC)u(t)iffx(t)(fk(b)12o+11fk+12fk)x(t)+2o1+12okkx(t)答案网ffx(t)=1(fk2i+12fk)x(t)+21i+12ikkx(t)http://www.daanwang.comRRCu(t)(R2-4(a)12oR1)u(t)2o12RiRCu(t)2iRu(t)(b)2RCCu(t1)2o(+RC2+21RCo+)uo(t)u(t)RCC1u(2)it2RC1i()uit()ut答案网（http://www.daanwang.com）（2-5题~2-10题）0.5t2-5(1)运动模态：ex()tt-202e.t5(2)0.5t3230.5t3运动模态：esinx2(tt)3esin2t(3)运动模态：(1+)te-tx(t)1(1tt)e22-6QPk2Qo2-7F12.11yeE(sin)()2-8ddooos24s2dc(t)2-9(s)k(t)(t)22ette(s1)(s2)dt答案网2-10t零初态c响应(t)1http://www.daanwang.com12ee2t2tt零输入c响应(t2)e2e总输出t2tc()tc(1)tc2()t14e2e答案网（http://www.daanwang.com）（2-11题~2-15题）C(100s)(4s1)2E10((s)12s23s5)2-112R12(ss)23sR2512(s)s223s25U(s)R(URo(Cs)s111)(oRoCs10)2-12()ao(R1Cs1)oo(b)U(s)RCsUi(s)Roio1U(s)(RRCs1)(b)o122Ui(s()RRo1R2)C2s1Uo(s)RR122-13323RUiR(s)Co1C1s2Ro2C1s2RR(s)K(s)K2-14m1m2Ua(sT)ms1Ma(sT)ms1uuuuuk1i12ami32ko2-15113s(Tms1)uo答案网uthttp://www.daanwang.com3kts111(os)31.262Ts((is1)m3kk3ktm)s331m.26kk答案网（http://www.daanwang.com）（2-17题~2-21题）C(sGG)CG(sG)(1HH)1212122-17(a)R(1s)GG(b)23R1(sG)1H11H2HC(s(GG)G)C(s)GGG)(c132(d)123R1(Gs)2H1G12G1GH2HR(s1)1GH22GH331GHGH133C(s)GGGG123C(GG)G(s)132)(e4(f)1R(Gs)H21G1G21H2G3G2HR(1s)G1G21HC(s)GGGC(Gs)(1GGH)2-18(a)1232121R1(Gs)1G2G12G1HN1(sG)1G2G12G1H(C1(sG))GGGGC(s)G(b)124344R(1s)G2G43G4GN1(sG)2G43G4G2-19与2-17同2-20与2-18同C(Gs)GGGG(1GH)2-21(a)12343111GHR(11sGH)32GGGHH123121132GHGH答案网E(s()1GH)GGHH3http://www.daanwang.com243211GHR(s11GH)32GGGHH123121132GHGHC(Gs)G2GGC(s)1GG(b)121212R1(sG)1